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a231348c · cprutean · c07be827 · a231348c
Commit a231348c authored 1 year ago by cprutean
--- a/CodeExamples/InsideSphere.ipynb
+++ b/CodeExamples/InsideSphere.ipynb
+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "id": "3afb0d80",
+   "metadata": {},
+   "source": [
+    "# Inside Sphere"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "id": "d7072d10",
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "\"\"\"   \n",
+    "    Demonstrate a logical function to test if  a point is inside or\n",
+    "    outside of a sphere of give radius.\n",
+    "\"\"\"\n",
+    "\n",
+    "import math\n",
+    "\n",
+    "def inside(radius, x, y, z):\n",
+    "    \"\"\"\n",
+    "    Check if point x,y,x is inside a sphere of radius r\n",
+    "    \"\"\"\n",
+    "    lenSqr = x*x + y*y + z*z      # length squared; this avoids sqrt() for efficiency.\n",
+    "    if lenSqr <= radius*radius :  # Is inside sphere\n",
+    "        return True               # Return logical True\n",
+    "    else:                         # Else outside\n",
+    "        return False              # Return logical False\n",
+    "\n",
+    "\n",
+    "def main():\n",
+    "    radius = 5.0\n",
+    "    x = float(input(\"X value : \"))\n",
+    "    y = float(input(\"Y value : \"))\n",
+    "    z = float(input(\"Z value : \"))\n",
+    "\n",
+    "    if inside(radius,x,y,z):    # Use the function above to do the work\n",
+    "        print(\"Point is inside sphere of radius : \" + str(radius))\n",
+    "    else:\n",
+    "        print(\"Point is outside sphere of radius : \" + str(radius))\n",
+    "\n",
+    "main()"
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 3 (ipykernel)",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
+   "version": "3.9.7"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 5
+}
+%% Cell type:markdown id:3afb0d80 tags:
+
+# Inside Sphere
+
+%% Cell type:code id:d7072d10 tags:
+
+``` python
+"""
+    Demonstrate a logical function to test if  a point is inside or
+    outside of a sphere of give radius.
+"""
+
+import math
+
+def inside(radius, x, y, z):
+    """
+    Check if point x,y,x is inside a sphere of radius r
+    """
+    lenSqr = x*x + y*y + z*z      # length squared; this avoids sqrt() for efficiency.
+    if lenSqr <= radius*radius :  # Is inside sphere
+        return True               # Return logical True
+    else:                         # Else outside
+        return False              # Return logical False
+
+
+def main():
+    radius = 5.0
+    x = float(input("X value : "))
+    y = float(input("Y value : "))
+    z = float(input("Z value : "))
+
+    if inside(radius,x,y,z):    # Use the function above to do the work
+        print("Point is inside sphere of radius : " + str(radius))
+    else:
+        print("Point is outside sphere of radius : " + str(radius))
+
+main()
+```