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luke naylor latex documents
research
Max Destabilizer Rank
Commits
7e8de853
Commit
7e8de853
authored
1 year ago
by
Luke Naylor
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Minor wording corrections
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#27733
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1 year ago
Stage: test
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main.tex
+10
-6
10 additions, 6 deletions
main.tex
with
10 additions
and
6 deletions
main.tex
+
10
−
6
View file @
7e8de853
...
...
@@ -238,15 +238,18 @@ Suppose that the following are satisfied:
\item
The pseudo-wall contains
$
p
$
in it's interior
(
$
P
$
can be chosen to be the base of the left branch to target all left-walls)
\item
$
u
$
destabilizes
$
v
$
going `inwards', that is,
$
\nu
_{
\alpha
,
\beta
}
(
u
)
<
\nu
_{
\alpha
,
\beta
}
(
v
)
$
outside the pseudo-wall, and
$
\nu
_{
\alpha
,
\beta
}
(
u
)
>
\nu
_{
\alpha
,
\beta
}
(
v
)
$
inside.
$
\nu
_{
\alpha
,
\beta
}
(
\pm
u
)
<
\nu
_{
\alpha
,
\beta
}
(
v
)
$
outside the pseudo-wall, and
$
\nu
_{
\alpha
,
\beta
}
(
\pm
u
)
>
\nu
_{
\alpha
,
\beta
}
(
v
)
$
inside.
Where we use
$
+
u
$
or
$
-
u
$
depending on whether
$
(
\beta
,
\alpha
)
$
is on the left
or right (resp.) of the characteristic vertical line for
$
u
$
.
\end{itemize}
\noindent
Then we have the following:
\begin{itemize}
\item
The pseudo-wall is left of
$
u
$
's vertical characteristic line
(if this is a real wall then
$
v
$
is being semistabilized by a positive rank object)
(if this is a real wall then
$
v
$
is being semistabilized by an object with
Chern character
$
u
$
, not
$
-
u
$
)
\item
$
\mu
(
u
)
<
\mu
(
v
)
$
, i.e.,
$
u
$
's vertical characteristic line is left of
$
v
$
's vertical
characteristic line
\item
$
\chern
_
2
^{
P
}
(
u
)
>
0
$
...
...
@@ -263,7 +266,7 @@ $\Delta(u),\Delta(v) \geq 0$.
For the forwards implication, assume that the suppositions of the lemma are
satisfied. The pseudo-wall intersects the characteristic hyperbola for
$
v
$
, at
some point
$
Q
$
further up the hyperbola branch than
$
P
$
(to satisfy second
supposition). At
$
Q
$
, we have
$
\
m
u
_
Q
(
v
)=
0
$
, and hence
$
\
m
u
_
Q
(
u
)=
0
$
too.
supposition). At
$
Q
$
, we have
$
\
n
u
_
Q
(
v
)=
0
$
, and hence
$
\
n
u
_
Q
(
u
)=
0
$
too.
This means that the characteristic hyperbola for
$
u
$
must intersect that of
$
v
$
at
$
Q
$
. Considering the shapes of the hyperbolae alone, there are 3 distinct
ways that they can intersect, as illustrated in Fig
...
...
@@ -273,11 +276,12 @@ $u$'s hyperbola, as well as the positions of the base.
However, considering the third supposition, only case 3 (green in figure) is
valid.
This is because we need
$
\nu
_{
\alpha
,
\beta
}
(
u
)
>
0
$
(
$
\nu
_{
\alpha
,
\beta
}
(-
u
)
>
0
$
in case 1 involving the right hyperbola branch)
(
or
$
\nu
_{
\alpha
,
\beta
}
(-
u
)
>
0
$
in case 1 involving the right hyperbola branch)
for points
$
(
\beta
,
\alpha
)
$
on
$
v
$
's characteristic curve inside the pseudo-wall.
In passing, note that this implies consequence 3.
Recalling how the sign of
$
\nu
_{
\alpha
,
\beta
}
(
\pm
u
)
$
changes
(illustrated in Fig
\ref
{
fig:charact
_
curves
_
vis
}
), we can eliminate cases 1 and
2.
In passing, this implies consequence 3.
2.
\begin{sagesilent}
def hyperbola
_
intersection
_
plot():
...
...
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