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luke naylor latex documents
research
Max Destabilizer Rank
Commits
e4cf3a42
Commit
e4cf3a42
authored
1 year ago
by
Luke Naylor
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Correct bgmlv2 'lowerbounds' to 'upperbounds'
parent
04e73735
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main.tex
+30
-18
30 additions, 18 deletions
main.tex
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30 additions
and
18 deletions
main.tex
+
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−
18
View file @
e4cf3a42
...
...
@@ -360,45 +360,45 @@ bgmlv2_d_ineq = (
).expand()
# Keep hold of lower bound for d
bgmlv2
_
d
_
low
erbound = bgmlv2
_
d
_
ineq.rhs()
bgmlv2
_
d
_
upp
erbound = bgmlv2
_
d
_
ineq.rhs()
\end{sagesilent}
\begin{equation}
\label
{
eqn-bgmlv2
_
d
_
low
erbound
}
\label
{
eqn-bgmlv2
_
d
_
upp
erbound
}
\sage
{
bgmlv2
_
d
_
ineq
}
\end{equation}
\begin{sagesilent}
# Seperate out the terms of the lower bound for d
bgmlv2
_
d
_
low
erbound
_
without
_
hyp = (
bgmlv2
_
d
_
low
erbound
bgmlv2
_
d
_
upp
erbound
_
without
_
hyp = (
bgmlv2
_
d
_
upp
erbound
.subs(1/r == 0)
)
bgmlv2
_
d
_
low
erbound
_
const
_
term = (
bgmlv2
_
d
_
low
erbound
_
without
_
hyp
bgmlv2
_
d
_
upp
erbound
_
const
_
term = (
bgmlv2
_
d
_
upp
erbound
_
without
_
hyp
.subs(r==0)
)
bgmlv2
_
d
_
low
erbound
_
linear
_
term = (
bgmlv2
_
d
_
low
erbound
_
without
_
hyp
- bgmlv2
_
d
_
low
erbound
_
const
_
term
bgmlv2
_
d
_
upp
erbound
_
linear
_
term = (
bgmlv2
_
d
_
upp
erbound
_
without
_
hyp
- bgmlv2
_
d
_
upp
erbound
_
const
_
term
).expand()
bgmlv2
_
d
_
low
erbound
_
exp
_
term = (
bgmlv2
_
d
_
low
erbound
- bgmlv2
_
d
_
low
erbound
_
without
_
hyp
bgmlv2
_
d
_
upp
erbound
_
exp
_
term = (
bgmlv2
_
d
_
upp
erbound
- bgmlv2
_
d
_
upp
erbound
_
without
_
hyp
).expand()
\end{sagesilent}
Viewing equation
\ref
{
eqn-bgmlv2
_
d
_
low
erbound
}
as a lower bound for
$
d
$
in term
Viewing equation
\ref
{
eqn-bgmlv2
_
d
_
upp
erbound
}
as a lower bound for
$
d
$
in term
of
$
r
$
again, there's a constant term
$
\sage
{
bgmlv
2
_
d
_
low
erbound
_
const
_
term
}$
,
$
\sage
{
bgmlv
2
_
d
_
upp
erbound
_
const
_
term
}$
,
a linear term
$
\sage
{
bgmlv
2
_
d
_
low
erbound
_
linear
_
term
}$
,
$
\sage
{
bgmlv
2
_
d
_
upp
erbound
_
linear
_
term
}$
,
and a hyperbolic term
$
\sage
{
bgmlv
2
_
d
_
low
erbound
_
exp
_
term
}$
.
$
\sage
{
bgmlv
2
_
d
_
upp
erbound
_
exp
_
term
}$
.
Notice that for
$
\beta
=
\beta
_{
-
}$
(or
$
\beta
_{
+
}$
), that is when
$
\chern
^{
\beta
}_
2
(
F
)=
0
$
, the constant and linear terms match up with the ones
for the bound found for
$
d
$
in subsection
\ref
{
subsect-d-bound-bgmlv1
}
.
...
...
@@ -554,10 +554,22 @@ Suppose we take $\beta = \beta_{-}$ in the previous subsections, to find all
circular walls to the left of the vertical wall (TODO as discussed in ref).
\begin{equation*}
\sage
{
bgmlv3
_
d
_
upperbound
_
const
_
term
}
d
\geq
\sage
{
bgmlv1
_
d
_
lowerbound
_
const
_
term
_
alt.subs(chbv == 0)
}
+
\sage
{
bgmlv1
_
d
_
lowerbound
_
linear
_
term
}
+
\sage
{
bgmlv1
_
d
_
lowerbound
_
exp
_
term
_
alt.subs(chbv == 0)
}
\end{equation*}
\begin{equation*}
\sage
{
bgmlv3
_
d
_
upperbound
_
const
_
term
_
alt1.subs(chbv == 0)
}
d
\geq
\sage
{
bgmlv2
_
d
_
lowerbound
_
const
_
term
}
+
\sage
{
bgmlv2
_
d
_
lowerbound
_
linear
_
term
}
+
\sage
{
bgmlv2
_
d
_
lowerbound
_
exp
_
term
}
\end{equation*}
\begin{equation*}
d
\leq
\sage
{
bgmlv3
_
d
_
upperbound
_
const
_
term
_
alt.subs(chbv == 0)
}
+
\sage
{
bgmlv3
_
d
_
upperbound
_
linear
_
term
}
+
\sage
{
bgmlv3
_
d
_
upperbound
_
exp
_
term
_
alt.subs(chbv == 0)
}
\end{equation*}
...
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